(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

ff

Q is empty.

(1) QTRS Reverse (EQUIVALENT transformation)

We applied the QTRS Reverse Processor [REVERSE].

(2) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

f'(x) → f'(x)

Q is empty.

(3) AAECC Innermost (EQUIVALENT transformation)

We have applied [NOC,AAECCNOC] to switch to innermost. The TRS R 1 is none

The TRS R 2 is

f'(x) → f'(x)

The signature Sigma is {f'}

(4) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

f'(x) → f'(x)

The set Q consists of the following terms:

f'(x0)

(5) DependencyPairsProof (EQUIVALENT transformation)

Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.

(6) Obligation:

Q DP problem:
The TRS P consists of the following rules:

F'(x) → F'(x)

The TRS R consists of the following rules:

f'(x) → f'(x)

The set Q consists of the following terms:

f'(x0)

We have to consider all minimal (P,Q,R)-chains.

(7) UsableRulesProof (EQUIVALENT transformation)

As all Q-normal forms are R-normal forms we are in the innermost case. Hence, by the usable rules processor [LPAR04] we can delete all non-usable rules [FROCOS05] from R.

(8) Obligation:

Q DP problem:
The TRS P consists of the following rules:

F'(x) → F'(x)

R is empty.
The set Q consists of the following terms:

f'(x0)

We have to consider all minimal (P,Q,R)-chains.

(9) QReductionProof (EQUIVALENT transformation)

We deleted the following terms from Q as each root-symbol of these terms does neither occur in P nor in R.[THIEMANN].

f'(x0)

(10) Obligation:

Q DP problem:
The TRS P consists of the following rules:

F'(x) → F'(x)

R is empty.
Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(11) NonTerminationProof (EQUIVALENT transformation)

We used the non-termination processor [FROCOS05] to show that the DP problem is infinite.
Found a loop by semiunifying a rule from P directly.

s = F'(x) evaluates to t =F'(x)

Thus s starts an infinite chain as s semiunifies with t with the following substitutions:
  • Matcher: [ ]
  • Semiunifier: [ ]




Rewriting sequence

The DP semiunifies directly so there is only one rewrite step from F'(x) to F'(x).



(12) NO